Lithium Hydroxide → HCID 86648661、化合物

HRID 43715ノート

反応式

HRID 43715 の反応式
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C@H:12]2[CH2:17][CH2:16][N:15]([C:18]3[S:19][C:20]([C:24]([O:26]CC)=[O:25])=[C:21]([CH3:23])[N:22]=3)[CH2:14][C@H:13]2[O:29][CH2:30][CH2:31][CH2:32][F:33])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+]>CO>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C@H:12]2[CH2:17][CH2:16][N:15]([C:18]3[S:19][C:20]([C:24]([OH:26])=[O:25])=[C:21]([CH3:23])[N:22]=3)[CH2:14][C@H:13]2[O:29][CH2:30][CH2:31][CH2:32][F:33])=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]

参加物

4

反応物 2

HCID 3939Lithium HydroxideHCID 86648662ethyl cis(+/-)-2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-(3-fluoropropoxy)piperidin-1-yl)-4-methyl-1,3-thiazole-5-carboxylate

生成物 1

HCID 86648661HCID 86648661、化合物収率 79%

試薬・触媒・溶媒 1

HCID 887Methanol溶媒

実験手順

The same operation as in Example (91d) was performed using ethyl cis(±)-2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}-3-(3-fluoropropoxy)piperidin-1-yl)-4-methyl-1,3-thiazole-5-carboxylate obtained in Example (129a) (0.20 g, 0.49 mmol), 2 N lithium hydroxide (6 mL, 12 mmol) and methanol (5 mL), to obtain 0.15 g of the title compound as a light brown solid (79%).

出典と根拠

ORDレコード
ord-8ca9977677324c29b18b23de93f1f0b7
出典データセット
uspto-grants-2013_09
特許番号
US08536197B2

反応ノート

読み込み中…