[CH2:1]([O:3][C:4]1[CH:5]=[C:6]2[C:11](=[CH:12][C:13]=1[OH:14])[N:10]=[C:9]([N:15]1[CH2:20][CH2:19][O:18][CH2:17][CH2:16]1)[N:8]=[C:7]2[N:21]1[CH2:26][CH2:25][CH:24]([N:27]2[C:36](=[O:37])[C:35]3[C:30](=[CH:31][CH:32]=[C:33]([CH3:38])[CH:34]=3)[N:29]([CH3:39])[C:28]2=[O:40])[CH2:23][CH2:22]1)[CH3:2].[CH2:41](I)[CH2:42][CH3:43]>>[CH2:1]([O:3][C:4]1[CH:5]=[C:6]2[C:11](=[CH:12][C:13]=1[O:14][CH2:41][CH2:42][CH3:43])[N:10]=[C:9]([N:15]1[CH2:20][CH2:19][O:18][CH2:17][CH2:16]1)[N:8]=[C:7]2[N:21]1[CH2:26][CH2:25][CH:24]([N:27]2[C:36](=[O:37])[C:35]3[C:30](=[CH:31][CH:32]=[C:33]([CH3:38])[CH:34]=3)[N:29]([CH3:39])[C:28]2=[O:40])[CH2:23][CH2:22]1)[CH3:2]The same procedure as in Example 48 was repeated, using 335 mg (0.61 mmol) of Compound 47 obtained in Example 47, except that propyl iodide was used in place of methyl iodide, to give 164 mg (yield: 46%) of Compound 49 as white crystals.
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