[Cl:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[C:13]([O:14]C)=[CH:12][CH:11]=[CH:10][C:9]=1[F:16]>Br>[Cl:1][C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][C:3]=1[C:8]1[C:13]([OH:14])=[CH:12][CH:11]=[CH:10][C:9]=1[F:16]Treatment of 2′-chloro-2-fluoro-6-methoxybiphenyl (17.0 g) with hydrogen bromide (33% in acetic acid, 60 mL) according to the procedure described for Example 69, Step 2 provided 7.5 g (57%) of 2′-chloro-6-fluorobiphenyl-2-ol as a colorless oil.
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