2,6-Lutidine → Methyl 4-(triisopropylsiloxy)phenylacetate

반응식

[OH:1][C:2]1[CH:7]=[CH:6][C:5]([CH2:8][C:9]([O:11][CH3:12])=[O:10])=[CH:4][CH:3]=1.N1C(C)=CC=CC=1C.[Si:21](OS(C(F)(F)F)(=O)=O)([CH:28]([CH3:30])[CH3:29])([CH:25]([CH3:27])[CH3:26])[CH:22]([CH3:24])[CH3:23]>C(Cl)Cl>[CH3:12][O:11][C:9](=[O:10])[CH2:8][C:5]1[CH:4]=[CH:3][C:2]([O:1][Si:21]([CH:28]([CH3:30])[CH3:29])([CH:25]([CH3:27])[CH3:26])[CH:22]([CH3:24])[CH3:23])=[CH:7][CH:6]=1

참가 물질

실험 절차

To methyl 2-(4-hydroxyphenyl)acetate (E1) in CH2Cl2 at 0° C. was added 2,6-lutidine and TIPS-OTf. The ice bath was removed and the solution was allowed to warm to room temperature and stirred. After 4 h the solution was poured into NH4Cl(sat) and CH2Cl2 and the organic layer was further extracted with NH4Cl(sat). The organics were dried (Na2SO4) filtered and evaporated. Column chromatography (0-15% EtOAc/Hexanes) gave pure methyl-2-(4-(triisopropylsilyloxy)phenyl)acetate (E2).