Hydrochloric Acid → HCID 12319472, 화합물

반응식

[Br:1][C:2]1[CH:15]=[CH:14][CH:13]=[CH:12][C:3]=1[CH:4]([OH:11])[C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][CH:6]=1.Cl.[CH3:17]O>>[CH3:17][O:11][CH:4]([C:5]1[CH:10]=[CH:9][CH:8]=[CH:7][CH:6]=1)[C:3]1[CH:12]=[CH:13][CH:14]=[CH:15][C:2]=1[Br:1]

참가 물질

반응물 3

HCID 313Hydrochloric Acid

HCID 887Methanol

HCID 114255182-Bromo-α-phenylbenzenemethanol

생성물 1

HCID 12319472HCID 12319472, 화합물

실험 절차

A solution of 152 g. of 2-bromobenzhydrol, 1 liter of methanol, and 45 ml. of conc. hydrochloric acid is heated under reflux for 24 hours, cooled, stirred with 100 g. of potassium carbonate, filtered, and distilled to provide 2-bromobenzhydryl methyl ether, b.p. 126°-128° (0.7 mm.).