Sodium Iodide → HCID 12884442, 화합물

HRID 1156997노트

반응식

HRID 1156997 반응식
[CH3:1][N:2]1[CH2:7][CH:6]=[C:5]([C:8]2[CH:13]=[CH:12][CH:11]=[C:10]([O:14][CH3:15])[CH:9]=2)[CH2:4][CH2:3]1.Cl[CH2:17][CH2:18][CH2:19]Br.[I-].[Na+]>>[CH3:15][O:14][C:10]1[CH:9]=[C:8]([C:5]23[CH2:19][CH2:18][CH2:17][C:4]2=[CH:3][N:2]([CH3:1])[CH2:7][CH2:6]3)[CH:13]=[CH:12][CH:11]=1

참가 물질

4

반응물 3

HCID 5238Sodium IodideHCID 80061-Bromo-3-chloropropaneHCID 1557781,2,3,6-Tetrahydro-4-(3-methoxyphenyl)-1-methylpyridine

생성물 1

HCID 12884442HCID 12884442, 화합물

실험 절차

Following the procedure set out in Example 47, 1-methyl-4-(3-methoxyphenyl)-1,2,3,6-tetrahydropyridine was reacted with 3-chloropropylbromide and sodium iodide to afford 4a-(3-methoxyphenyl)-2-methyl-3,4,4a,5,6,7-hexahydro-2-pyrindine. B.P. 132°-134° C. at 0.1 torr.

출처 및 근거

ORD 기록
ord-b8e73c9c7c6c4c219c7a62029f834529
출처 데이터셋
uspto-grants-1982_06
특허 번호
US04337341

반응 노트

불러오는 중…