Sulfate Ion → Calcium Sulfate, Hemihydrate

반응식

[S:1](=[O:5])(=[O:4])([OH:3])[OH:2].[S:6]([O-:10])([O-:9])(=[O:8])=[O:7].[Ca:11].[O-]P([O-])([O-])=O.[O-]P([O-])([O-])=O.[O-]P([O-])([O-])=O.[F-].[Ca+2].[Ca+2].[Ca+2].[Ca+2].[Ca+2]>>[OH2:2].[S:6]([O-:10])([O-:9])(=[O:8])=[O:7].[Ca+2:11].[Ca+2:11].[S:1]([O-:5])([O-:4])(=[O:3])=[O:2]

참가 물질

반응물 4

HCID 1117Sulfate Ion3회

HCID 1118Sulfuric Acid

HCID 5460341Calcium

HCID 10207414Fluorapatite (Ca5F(PO4)3)

생성물 1

HCID 3033839Calcium Sulfate, Hemihydrate

실험 절차

Sulfuric acid is added in amounts such that the sulfate content of the added acid and the sulfate content of the added rock is equivalent to about 90% to about 100% (more preferred 93-99.5%) of the stoichiometric amount of sulfate required to react with calcium added in the phosphate rock to form calcium sulfate hemihydrate.