Benzyl Chloride → Methyl 3-benzyl-4-iodobenzoate

반응식

[CH2:1](Cl)[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1.O[C:10]1[CH:11]=[C:12]([CH:17]=[CH:18][C:19]=1[I:20])[C:13]([O:15][CH3:16])=[O:14].C(=O)([O-])[O-].[K+].[K+]>C(C(C)=O)C>[CH2:1]([C:10]1[CH:11]=[C:12]([CH:17]=[CH:18][C:19]=1[I:20])[C:13]([O:15][CH3:16])=[O:14])[C:2]1[CH:7]=[CH:6][CH:5]=[CH:4][CH:3]=1

참가 물질

실험 절차

47 ml (411 mmol) of benzyl chloride are added to a solution of 104 g (374 mmol) of methyl 3-hydroxy-4-iodobenzoate and 103 g (748 mmol) of potassium carbonate in 600 ml of methyl ethyl ketone, and the reaction medium is then refluxed for 8 hours. After cooling, the reaction medium is filtered, the precipitate is rinsed with ethyl acetate and the filtrate is evaporated to dryness. The residue is taken up in a mixture of water and ethyl acetate. The organic phase is dried over sodium sulfate, filtered and evaporated. 139 g (100%) of methyl 3-benzyl-4-iodobenzoate are obtained in the form of a white solid.