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Methanol → HCID 60135868, 화합물

HRID 1425049
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HRID 1425049 반응식
[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][CH:20]=[C:21]([C:23]([O:25]C)=[O:24])[N:22]=3)=[CH:14][CH:13]=2)=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8].[OH-].[Li+].CO>O1CCCC1>[Cl:1][C:2]1[N:3]=[C:4]([C:9]([NH:11][C:12]2[CH:17]=[CH:16][C:15]([C:18]3[O:19][CH:20]=[C:21]([C:23]([OH:25])=[O:24])[N:22]=3)=[CH:14][CH:13]=2)=[O:10])[NH:5][C:6]=1[CH2:7][CH3:8]
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

5

반응물 3

HCID 887MethanolHCID 3939Lithium HydroxideHCID 67549191Methyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}phenyl)-1,3-oxazole-4-carboxylate

생성물 1

HCID 60135868HCID 60135868, 화합물수율 48.5%

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매

실험 절차

The same operation as in Example (91d) was performed using methyl 2-(4-{[(4-chloro-5-ethyl-1H-imidazol-2-yl)carbonyl]amino}phenyl)-1,3-oxazole-4-carboxylate obtained in Example (96c) (0.12 g, 0.32 mmol), 2 N lithium hydroxide (2 mL, 4 mmol), methanol (3 mL) and tetrahydrofuran (5 mL), to obtain 56 mg of the title compound as a light brown solid (48%).

출처 및 근거

ORD 기록
ord-3242a9da267b42bfbe834286fdd1d338
출처 데이터셋
uspto-grants-2015_01
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US08927588B2

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