3-(Boc-amino)piperidine → Hydrochloric Acid

반응식

[Br:1][C:2]1[C:11]2[C:10]([S:12]([Cl:15])(=[O:14])=[O:13])=[CH:9][CH:8]=[CH:7][C:6]=2[CH:5]=[N:4][CH:3]=1.[C:16]([O:20][C:21]([NH:23][CH:24]1[CH2:29][CH2:28][CH2:27][NH:26][CH2:25]1)=[O:22])([CH3:19])([CH3:18])[CH3:17]>>[C:16]([O:20][C:21]([NH:23][CH:24]1[CH2:29][CH2:28][CH2:27][N:26]([S:12]([C:10]2[C:11]3[C:2]([Br:1])=[CH:3][N:4]=[CH:5][C:6]=3[CH:7]=[CH:8][CH:9]=2)(=[O:14])=[O:13])[CH2:25]1)=[O:22])([CH3:19])([CH3:17])[CH3:18].[NH2:23][CH:24]1[CH2:29][CH2:28][CH2:27][N:26]([S:12]([C:10]2[C:11]3[C:2]([Br:1])=[CH:3][N:4]=[CH:5][C:6]=3[CH:7]=[CH:8][CH:9]=2)(=[O:14])=[O:13])[CH2:25]1.[ClH:15]

참가 물질

반응물 2

HCID 42330413-(Boc-amino)piperidine

HCID 145800584-Bromo-5-isoquinolinesulfonyl chloride

생성물 3

HCID 313Hydrochloric Acid

HCID 67242500(r/s)-3-Amino-1-(4-bromo-5-isoquinolinesulfonyl)piperidine

HCID 67242812(r/s)-3-(Tert-butoxycarbonylamino)-1-(4-bromo-5-isoquinolinesulfonyl)piperidine

실험 절차

(R/S)-3-(tert-Butoxycarbonylamino)-1-(4-bromo-5-isoquinolinesulfonyl)-piperidine (Intermediate 2) is prepared from 4-bromo-5-isoquinolinesulfonyl chloride and 3-(tert-butoxycarbonylamino)piperidine (AstaTech) according to the method described in Example 1, Step A, and then used in the method of Example 1, Step B in a similar manner to obtain the title compound as hydrochloride.