Methylparaben → 2-Methoxyethyl 4-hydroxybenzoate

HRID 1439924노트

반응식

HRID 1439924 반응식
[Na].[OH:2][C:3]1[CH:12]=[CH:11][C:6]([C:7]([O:9][CH3:10])=[O:8])=[CH:5][CH:4]=1.[CH3:13][O:14][CH2:15]CO>>[OH:2][C:3]1[CH:4]=[CH:5][C:6]([C:7]([O:9][CH2:10][CH2:13][O:14][CH3:15])=[O:8])=[CH:11][CH:12]=1

참가 물질

4

실험 절차

In the first step (as in the Example 4) 1 g (43 mmol) of sodium was dissolved in 25 ml of 2-methoxyethanol. An amount of 3.0 g (22 mmol) of methyl 4-hydroxy-benzoate was added, producing 2-methoxyethyl 4-hydroxybenzoate, as a colourless oil, in essentially quantitative yield.

출처 및 근거

ORD 기록
ord-303525d959964b53b89846a03c418f46
출처 데이터셋
uspto-grants-1996_03
특허 번호
US05496854

반응 노트

불러오는 중…