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1H-Indazol-4-amine, 1-methyl- → HCID 68682622, 화합물

HRID 1444469
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HRID 1444469 반응식
[CH3:1][O:2][C:3]1[CH:8]=[CH:7][CH:6]=[CH:5][C:4]=1[C:9]([CH3:20])([CH3:19])[CH2:10][C:11]([OH:18])([C:14]([F:17])([F:16])[F:15])[CH:12]=O.[NH2:21][C:22]1[CH:30]=[CH:29][CH:28]=[C:27]2[C:23]=1[CH:24]=[N:25][N:26]2[CH3:31]>[Ti](Cl)(Cl)(Cl)Cl>[CH3:31][N:26]1[C:27]2[C:23](=[C:22]([NH:21][CH:12]3[C:5]4[C:4](=[C:3]([O:2][CH3:1])[CH:8]=[CH:7][CH:6]=4)[C:9]([CH3:20])([CH3:19])[CH2:10][C:11]3([C:14]([F:15])([F:17])[F:16])[OH:18])[CH:30]=[CH:29][CH:28]=2)[CH:24]=[N:25]1
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

4

반응물 2

HCID 1538381H-Indazol-4-amine, 1-methyl-HCID 179890984-(2-Methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal

생성물 1

HCID 68682622HCID 68682622, 화합물수율 23.4%

시약·촉매·용매 1

HCID 24193Titanium Tetrachloride촉매

실험 절차

Analogously to Example 3, the corresponding imine is produced starting from 296 mg of 4-(2-methoxyphenyl)-2-hydroxy-4-methyl-2-(trifluoromethyl)pentanal and 150 mg of 4-amino-1-methylindazole. By reaction of 100 mg of the imine with 0.5 ml of titanium tetrachloride, 100 mg of the title compound is obtained.

출처 및 근거

ORD 기록
ord-e7b4719d83914599a5a393abd9652a7d
출처 데이터셋
uspto-grants-2010_02
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07662821B2

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