Hydrochloric Acid → 3-[3-(3-Thienyl)phenoxy]propanal

반응식

C[O:2][CH:3](OC)[CH2:4][CH2:5][O:6][C:7]1[CH:12]=[CH:11][CH:10]=[C:9]([C:13]2[CH:17]=[CH:16][S:15][CH:14]=2)[CH:8]=1.Cl.C(=O)(O)[O-].[Na+]>O1CCCC1>[S:15]1[CH:16]=[CH:17][C:13]([C:9]2[CH:8]=[C:7]([CH:12]=[CH:11][CH:10]=2)[O:6][CH2:5][CH2:4][CH:3]=[O:2])=[CH:14]1

참가 물질

실험 절차

0.46 g of the resulting ether compound was dissolved in 5 ml of tetrahydrofuran, and 2 ml of 2N hydrochloric acid was added. The mixture was allowed to stand at room temperature for 4 hours, and then the solution was made basic with an aqueous solution of sodium bicarbonate. The solution was extracted with s ethyl acetate, and the extract was worked up in a customary manner. The product was purified by silica gel column chromatography [hexane / ethyl acetate =20/1→10/1] to give 0.28 g of 3-[3-(3-thienyl)phenoxy]propanal as a colorless oil.