[F:1][C:2]1[CH:3]=[C:4]([CH2:11]O)[CH:5]=[C:6]([F:10])[C:7]=1[S:8][CH3:9].[Br-:13].FC1C=C(C=C(F)C=1SC)C=O>>[Br:13][CH2:11][C:4]1[CH:5]=[C:6]([F:10])[C:7]([S:8][CH3:9])=[C:2]([F:1])[CH:3]=1The product from step B was converted to the bromide according to the procedure from intermediate 5 (step A). 1H NMR (500 MHz, CDCl3) δ 7.36 (d, J 7.5 Hz, 2H), 4.82 (s, 2H), 2.88 (s, 3H)
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