Sodium Hydroxide → HCID 89501036, 화합물
반응식
[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([O:12]C)=[O:11])[CH:7]=1.[OH-].[Na+]>CO.C1COCC1>[Cl:1][C:2]1[C:3]([F:19])=[CH:4][C:5]([N:14]2[CH:18]=[N:17][N:16]=[N:15]2)=[C:6](/[CH:8]=[CH:9]/[C:10]([OH:12])=[O:11])[CH:7]=1참가 물질
5
실험 절차
To Intermediate 5C (5 g, 17.7 mmol) in MeOH (50 mL) and THF (25 mL) was added 10% NaOH solution (25 mL). After 2 h, the reaction was concentrated and the residue was diluted with H2O. The pH was adjusted to 2 to 3 with 1.5 N HCl and the resultant solid was filtered and washed with petroleum ether to afford 2 g of Intermediate 5. MS (ESI) m/z: 269.0 (M+H)+.
후처리
- concentrationthe reaction was concentrated
- additionthe residue was diluted with H2O
- filtrationthe resultant solid was filtered
- washwashed with petroleum ether
출처 및 근거
- ORD 기록
- ord-f113eadd17b046029e4aaa97ee2043d0
- 출처 데이터셋
- uspto-grants-2015_07
- 특허 번호
- US09079929B2
반응 노트
불러오는 중…