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Lithium Hydroxide → 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylic acid

HRID 1529442
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반응식

HRID 1529442 반응식
[I:1][C:2]1[C:10]2[C:5](=[CH:6][CH:7]=[C:8]([C:11]([O:13]C)=[O:12])[CH:9]=2)[N:4]([CH:15]2[CH2:20][CH2:19][CH2:18][CH2:17][O:16]2)[N:3]=1.[Li+].[OH-]>C1COCC1.CO>[I:1][C:2]1[C:10]2[C:5](=[CH:6][CH:7]=[C:8]([C:11]([OH:13])=[O:12])[CH:9]=2)[N:4]([CH:15]2[CH2:20][CH2:19][CH2:18][CH2:17][O:16]2)[N:3]=1
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

4

반응물 2

HCID 3939Lithium HydroxideHCID 67959982methyl 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylate

생성물 1

HCID 679598343-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylic acid수율 87%

시약·촉매·용매 1

HCID 21899815MeOH tetrahydrofuran용매

실험 절차

To a solution of methyl 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylate ((5.0 g, 12.9 mmol) in THF: MeOH (70:30) (50 mL) was added LiOH (3.10 g, 129.0 mmol) in one lot and the reaction was stirred at RT for 12 h. The solvent were removed in vacuo and the residue was diluted with water and quenched with 1N HCl (50 mL) to obtain off white precipitate. The suspension was stirred for 10 min and filtered and dried to give 3-iodo-1-(tetrahydro-2H-pyran-2-yl)-1H-indazole-5-carboxylic acid (4.2 g, 87%) as an off white solid. 1H NMR (400 MHz, DMSO-d6) δ ppm 13.09 (s, 1H), 8.03-8.06 (m, 2H), 7.84-7.86 (m, 1H), 5.93 (dd, 1 H, J=9.7, 2.3 Hz), 3.90 (d, 1 H, J=11.9 Hz), 3.74-3.76 (m, 1H), 2.35-2.41 (m, 1H), 1.97-2.00 (m, 2H), 1.69-1.80 (m, 1H), 1.41-1.58 (m, 2H).

후처리

  1. customThe solvent were removed in vacuo
  2. additionthe residue was diluted with water
  3. customquenched with 1N HCl (50 mL)
  4. customto obtain off white precipitate
  5. stirringThe suspension was stirred for 10 min
  6. filtrationfiltered
  7. customdried

출처 및 근거

ORD 기록
ord-b9684e8207124513840230ef6a787be4
출처 데이터셋
uspto-grants-2015_07
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US09090593B2

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