Hydrochloric Acid → 4hydroxy-L-proline ethyl ester hydrochloride
반응식
[CH2:1]([O:3][C:4](=[O:21])[C@@H:5]1[CH2:9][CH:8]([OH:10])[CH2:7][N:6]1C(OCC1C=CC=CC=1)=O)[CH3:2].[ClH:22]>C(O)C.[Pd]>[ClH:22].[CH2:1]([O:3][C:4](=[O:21])[C@@H:5]1[CH2:9][CH:8]([OH:10])[CH2:7][NH:6]1)[CH3:2]참가 물질
5
실험 절차
To a solution of N-Cbz-4-hydroxy-L-proline ethyl ester (3.29 g) in 40 ml ethanol was added 6 ml of ethanol saturated with gaseous HCl followed by 10% palladium on carbon (0.50 g). The mixture was hydrogenated on a Parr Hydrogenator at 30-40 psi for 3 hours. The solution was filtered over celite and concentrated in vacuo to provide 2.09 g of the crystalline product.
후처리
- filtrationThe solution was filtered over celite and
- concentrationconcentrated in vacuo
출처 및 근거
- ORD 기록
- ord-df2c37ad716a4685b353dc050e3e951c
- 출처 데이터셋
- uspto-grants-1985_11
- 특허 번호
- US04555508
반응 노트
불러오는 중…