Hydrochloric Acid → 4-Biphenylylacetic acid methyl ester

HRID 1594680노트

반응식

HRID 1594680 반응식
[C:1]1([C:11]2[CH:16]=[CH:15][CH:14]=[CH:13][CH:12]=2)[CH:6]=[CH:5][C:4]([CH2:7][C:8]([OH:10])=[O:9])=[CH:3][CH:2]=1.Cl.[CH3:18]O>>[CH3:18][O:9][C:8](=[O:10])[CH2:7][C:4]1[CH:3]=[CH:2][C:1]([C:11]2[CH:12]=[CH:13][CH:14]=[CH:15][CH:16]=2)=[CH:6][CH:5]=1

참가 물질

4

반응물 3

HCID 313Hydrochloric AcidHCID 887MethanolHCID 3332Felbinac

생성물 1

HCID 30808634-Biphenylylacetic acid methyl ester수율 98%

실험 절차

To a solution of 4-biphenylacetic acid (10 g, 47 mmol) in methanol (150 mL) was added concentrated HCl (3 mL). The mixture was heated under reflux for 16 hours, cooled to rt, and the solvent was evaporated. Chromatography of the residue over silica gel (petroleum ether followed by ethyl acetate/petroleum ether 1/4) gave 4-biphenylacetic acid methyl ester (10.4 g, 98%).

후처리

  1. temperatureThe mixture was heated
  2. temperatureunder reflux for 16 hours
  3. customthe solvent was evaporated

출처 및 근거

ORD 기록
ord-89f6f13aa6804b27a5cefe72be011ca9
출처 데이터셋
uspto-grants-2001_09
특허 번호
US06284768B1

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