1,4-Dibromobutane → HCID 22252321, 화합물

HRID 1612002

반응식

HRID 1612002 반응식
[CH3:1][O:2][C:3]1[C:8]([O:9][CH3:10])=[C:7]([O:11][CH3:12])[CH:6]=[CH:5][C:4]=1[OH:13].[Br:14][CH2:15][CH2:16][CH2:17][CH2:18]Br>>[Br:14][CH2:15][CH2:16][CH2:17][CH2:18][O:13][C:4]1[CH:5]=[CH:6][C:7]([O:11][CH3:12])=[C:8]([O:9][CH3:10])[C:3]=1[O:2][CH3:1]

참가 물질

3

반응물 2

HCID 80561,4-DibromobutaneHCID 6035772,3,4-Trimethoxyphenol

생성물 1

HCID 22252321HCID 22252321, 화합물

실험 절차

The procedure is as for Example 53, Step A, using as substrate 2,3,4-trimethoxyphenol and 1,4-dibromobutane.

출처 및 근거

ORD 기록
ord-997f9511402b4c18a4bc7117c644fefb
출처 데이터셋
uspto-grants-2006_01
특허 번호
US06992085B2

연결된 노트

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