Hydroxyamine hydrochloride → 4-[4-[(3E)-3-hydroxyimino-3-(1-methyl-6-oxo-3-pyridinyl)-1-(2-methylphenyl)propyl]phenyl]benzoic acid
반응식
[CH3:1][N:2]1[C:7](=[O:8])[CH:6]=[CH:5][C:4]([C:9](=O)[CH2:10][CH:11]([C:19]2[CH:24]=[CH:23][C:22]([C:25]3[CH:30]=[CH:29][C:28]([C:31]([OH:33])=[O:32])=[CH:27][CH:26]=3)=[CH:21][CH:20]=2)[C:12]2[CH:17]=[CH:16][CH:15]=[CH:14][C:13]=2[CH3:18])=[CH:3]1.Cl.[NH2:36][OH:37].C([O-])(O)=O.[Na+]>>[OH:37]/[N:36]=[C:9](/[C:4]1[CH:5]=[CH:6][C:7](=[O:8])[N:2]([CH3:1])[CH:3]=1)\[CH2:10][CH:11]([C:19]1[CH:20]=[CH:21][C:22]([C:25]2[CH:30]=[CH:29][C:28]([C:31]([OH:33])=[O:32])=[CH:27][CH:26]=2)=[CH:23][CH:24]=1)[C:12]1[CH:17]=[CH:16][CH:15]=[CH:14][C:13]=1[CH3:18]참가 물질
4
반응물 3
생성물 1
실험 절차
In analogy to example 151, step 3, 4′-[3-(1-methyl-6-oxo-1,6-dihydro-pyridin-3-yl)-3-oxo-1-o-tolyl-propyl]-biphenyl-4-carboxylic acid was reacted with hydroxylamine hydrochloride in the presence of NaHCO3 to give the title compound as a colorless solid, MS (ESI+): m/z=467.3 [M+H]+.