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Methyl Methacrylate → HCID 20273141, 화합물

HRID 1701084
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HRID 1701084 반응식
[C:1]([O-:6])(=[O:5])[C:2]([CH3:4])=[CH2:3].[CH2:7]([Sn+:11]([CH2:16][CH2:17][CH2:18][CH3:19])[CH2:12][CH2:13][CH2:14][CH3:15])[CH2:8][CH2:9][CH3:10].[C:20]([O:25][CH3:26])(=[O:24])[C:21]([CH3:23])=[CH2:22].C(OOC(=O)C1C=CC=CC=1)(=O)C1C=CC=CC=1>C1(C)C(C)=CC=CC=1>[CH3:26][O:25][C:20](=[O:24])[C:21]([CH3:23])=[CH2:22].[C:1]([O-:6])(=[O:5])[C:2]([CH3:4])=[CH2:3].[CH2:16]([Sn+:11]([CH2:7][CH2:8][CH2:9][CH3:10])[CH2:12][CH2:13][CH2:14][CH3:15])[CH2:17][CH2:18][CH3:19]
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

5

반응물 3

HCID 6658Methyl MethacrylateHCID 7187Benzoyl PeroxideHCID 21946344Tributyl tin methacrylate

생성물 1

HCID 20273141HCID 20273141, 화합물

시약·촉매·용매 1

HCID 7237O-Xylene용매

실험 절차

65 parts tributyl tin methacrylate and 35 parts methyl methacrylate were copolymerised in xylene using benzoyl peroxide initiator by the process described in Example 1 to form a 40 percent solids tributyl tin methacrylate methyl methacrylate copolymer solution. This 40 percent copolymer solution was used in the formulation of Example 5 to replace the copolymer solution of Example 1 and the ingredients were blended to form a paint.

출처 및 근거

ORD 기록
ord-0e0d3fc98ba34bd7b1f7bbf1dce09f16
출처 데이터셋
uspto-grants-1980_03
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US04191579

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