4-Chlorobenzotrichloride → HCID 14786574, 화합물

HRID 1701109

반응식

HRID 1701109 반응식
[Cl-].[Al+3].[Cl-].[Cl-].S(Cl)SCl.S(Cl)(Cl)(=O)=O.[Cl:14]C1C=CC(C(Cl)(Cl)Cl)=CC=1.[Cl:25][C:26]1[CH:27]=[C:28]([C:33]([Cl:36])([Cl:35])[Cl:34])[CH:29]=[CH:30][C:31]=1[Cl:32]>>[Cl:14][C:29]1[CH:30]=[C:31]([Cl:32])[C:26]([Cl:25])=[CH:27][C:28]=1[C:33]([Cl:36])([Cl:34])[Cl:35]

참가 물질

6

반응물 5

HCID 212774-Chlorobenzotrichloride2회HCID 24648Sulfuryl chloride2회HCID 24807Sulfur monochlorideHCID 256083,4-DichlorophenyltrichloromethaneHCID 6451240Aluminum(III) Chloride

생성물 1

HCID 14786574HCID 14786574, 화합물수율 47%

실험 절차

A solution of 4.6 g (34 mmol) of aluminum chloride and 4.6 g (34 mmol) of disulphur dichloride in 344 g (2.55 mol) of sulphuryl chloride was added dropwise to a mixture of 57.5 g (250 mmol) of p-chlorobenzotrichloride and 115 g (850 mmol) of sulphuryl chloride at 40° C. The reaction mixture was further processed in the manner described in Example 5, that is to say that, after the working up, unreacted p-chlorobenzotrichloride and 3,4-dichlorobenzotrichloride were separated off by distillation and fed to renewed chlorination with sulphuryl chloride under the conditions given here. By distillation of the combined sump fractions, 2,4,5-trichlorobenzotrichloride was obtained in a yield of 47% of theory.

후처리

  1. customwere separated off by distillation and fed
  2. distillationBy distillation of the combined sump fractions

출처 및 근거

ORD 기록
ord-52cf572afbf74898ac1c65e3b0945300
출처 데이터셋
uspto-grants-1980_03
특허 번호
US04191711

연결된 노트

불러오는 중…