[OH:1][C:2]1[C:11]2[C:6](=[C:7]3[CH:15]=[CH:14][CH:13]=[C:12]([CH3:16])[C:8]3=[CH:9][CH:10]=2)[O:5][C:4](=[O:17])[CH:3]=1.CC(O)=O.Cl[CH2:23][C:24](=O)[CH3:25]>C1(C)C=CC=CC=1.CCO.O>[CH3:16][C:12]1[C:8]2[CH:9]=[CH:10][C:11]3[C:2]4[O:1][CH:23]=[C:24]([CH3:25])[C:3]=4[C:4](=[O:17])[O:5][C:6]=3[C:7]=2[CH:15]=[CH:14][CH:13]=1To a solution of 7 (50 mg, 0.22 mmol) in toluene (8 mL) was added a mixture of HOAc (66 mg, 1.1 mmol) and NH4OAc (80 mg, 1.1 mmol) in EtOH (2 mL) and chloroacetone (103 mg, 1.1 mmol). The mixture was refluxed 24 h. After cooling, the mixture was diluted with H2O and extracted with EtOAc. The organic layer was dried over Na2SO4, filtered, and evaporated. The residue was purified by column chromatography to give 1 (35 mg, 60%) as a white solid. The spectroscopic data of synthetic compound 1 were identical with those of the natural product 1.
불러오는 중…