Lithium Hydroxide → 2-Chloro-4-(3-fluoro-4-(thiazol-4-yl)phenylamino)pyrimidine-5-carboxylic acid
반응식
[Cl:1][C:2]1[N:7]=[C:6]([NH:8][C:9]2[CH:14]=[CH:13][C:12]([C:15]3[N:16]=[CH:17][S:18][CH:19]=3)=[C:11]([F:20])[CH:10]=2)[C:5]([C:21]([O:23]CC)=[O:22])=[CH:4][N:3]=1.[Li+].[OH-]>C1COCC1>[Cl:1][C:2]1[N:7]=[C:6]([NH:8][C:9]2[CH:14]=[CH:13][C:12]([C:15]3[N:16]=[CH:17][S:18][CH:19]=3)=[C:11]([F:20])[CH:10]=2)[C:5]([C:21]([OH:23])=[O:22])=[CH:4][N:3]=1참가 물질
4
실험 절차
To a suspension of ethyl 2-chloro-4-(3-fluoro-4-(thiazol-4-yl)phenylamino)pyrimidine-5-carboxylate (186 mg, 0.491 mmol) in THF (4 mL), aq. 1N LiOH (1.00 mL, 1.00 mmol) was added. The suspension became clear with stirring. The mixture was then stirred at room temperature overnight. Upon acidification of the mixture with 1N HCl, white solids precipitated out, which were collected, and dried on vacuum to give 2-chloro-4-(3-fluoro-4-(thiazol-4-yl)phenylamino)pyrimidine-5-carboxylic acid (158 mg). MS 351.2 and 353.3 (M+H, Cl pattern)