Sodium Hydroxide → 6-(4-Methoxyphenyl)nicotinic acid

반응식

[CH3:1][O:2][C:3]1[CH:8]=[CH:7][C:6]([C:9]2[CH:18]=[CH:17][C:12]([C:13]([O:15]C)=[O:14])=[CH:11][N:10]=2)=[CH:5][CH:4]=1.[OH-].[Na+]>>[CH3:1][O:2][C:3]1[CH:4]=[CH:5][C:6]([C:9]2[CH:18]=[CH:17][C:12]([C:13]([OH:15])=[O:14])=[CH:11][N:10]=2)=[CH:7][CH:8]=1

참가 물질

반응물 2

HCID 14798Sodium Hydroxide

HCID 18625729HCID 18625729, 화합물

생성물 1

HCID 186259336-(4-Methoxyphenyl)nicotinic acid수율 70.7%

실험 절차

In a similar manner to that described in Example 2, a reaction was carried out using methyl 6-(4-methoxyphenyl)nicotinate (3.95 g) and aqueous sodium hydroxide solution (1N, 32.5 ml) and the reaction mixture was treated to afford the title compound (2.63 g) as colorless crystals.

후처리

additionthe reaction mixture was treated

출처 및 근거

ORD 기록: ord-e70ca072ff05452e8dda5e203b16360c
출처 데이터셋: uspto-grants-2003_03
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US06528525B1

반응 노트

불러오는 중…