Sodium hydride → HCID 18625893, 화합물
반응식
[N:1]1[CH:6]=[CH:5][CH:4]=[CH:3][C:2]=1[C:7]1[CH:26]=[CH:25][C:10]([C:11]([NH:13][CH2:14][CH2:15][CH2:16][C:17]2[CH:24]=[CH:23][C:20]([CH2:21]Cl)=[CH:19][CH:18]=2)=[O:12])=[CH:9][CH:8]=1.[H-].[Na+].[C:29]1([CH2:35][CH2:36][CH2:37][CH:38]([C:49]([O-:51])=[O:50])[C:39]([O:41][CH2:42][C:43]2[CH:48]=[CH:47][CH:46]=[CH:45][CH:44]=2)=[O:40])[CH:34]=[CH:33][CH:32]=[CH:31][CH:30]=1>>[C:29]1([CH2:35][CH2:36][CH2:37][C:38]([CH2:21][C:20]2[CH:23]=[CH:24][C:17]([CH2:16][CH2:15][CH2:14][NH:13][C:11](=[O:12])[C:10]3[CH:25]=[CH:26][C:7]([C:2]4[CH:3]=[CH:4][CH:5]=[CH:6][N:1]=4)=[CH:8][CH:9]=3)=[CH:18][CH:19]=2)([C:49]([O:51][CH2:2][C:7]2[CH:26]=[CH:25][CH:10]=[CH:9][CH:8]=2)=[O:50])[C:39]([O:41][CH2:42][C:43]2[CH:44]=[CH:45][CH:46]=[CH:47][CH:48]=2)=[O:40])[CH:34]=[CH:33][CH:32]=[CH:31][CH:30]=1참가 물질
4
실험 절차
In a similar manner to that described in Reference example 2(a), a reaction was carried out using 4-[3-(4-pyridine-2-ylbenzoylamino)propyl]benzylchloride (488 mg), which is the product of Reference example 50(c), sodium hydride (55% suspension in oil, 64 mg) and benzyl (3-phenylpropyl)malonate (540 mg) and the reaction mixture was treated to afford the title compound (0.65 g) as a syrup.
후처리
- additionthe reaction mixture was treated