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Water → HCID 11620341, 화합물

HRID 1865452
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HRID 1865452 반응식
[OH-].[Na+].[CH2:3]([O:10][C@@H:11]([CH2:16][C:17]1[CH:22]=[CH:21][C:20]([C:23]2[CH:28]=[CH:27][CH:26]=[C:25]([N:29]([CH3:40])[C:30]([NH:32][CH2:33][CH2:34][CH2:35][CH2:36][CH2:37][CH2:38][CH3:39])=[O:31])[CH:24]=2)=[CH:19][CH:18]=1)[C:12]([O:14]C)=[O:13])[C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1.O1CCCC1.CO.O>C(O)(=O)C>[CH2:3]([O:10][C@@H:11]([CH2:16][C:17]1[CH:22]=[CH:21][C:20]([C:23]2[CH:28]=[CH:27][CH:26]=[C:25]([N:29]([CH3:40])[C:30]([NH:32][CH2:33][CH2:34][CH2:35][CH2:36][CH2:37][CH2:38][CH3:39])=[O:31])[CH:24]=2)=[CH:19][CH:18]=1)[C:12]([OH:14])=[O:13])[C:4]1[CH:9]=[CH:8][CH:7]=[CH:6][CH:5]=1
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

6

반응물 4

HCID 962WaterHCID 14798Sodium HydroxideHCID 21899815MeOH tetrahydrofuranHCID 67304752HCID 67304752, 화합물

생성물 1

HCID 11620341HCID 11620341, 화합물수율 72%

시약·촉매·용매 1

HCID 176Acetic Acid용매

실험 절차

16 mg (0.4 mmol) of sodium hydroxide are added to a solution of 70 mg (0.42 mmol) of methyl (S)-2-benzyloxy-3-[3′-(3-heptyl-1-methylureido)biphenyl-4-yl]propanoate in 2 ml of 9/1 tetrahydrofuran/methanol. The reaction mixture is stirred overnight at ambient temperature. The reaction is halted by the addition of 2 ml of water and 0.5 ml of acetic acid, and then extraction is carried out with ethyl acetate. The organic phases are combined and dried over sodium sulfate. The solvents are evaporated and then the residue is chromatographed on silica gel (dichloromethane/methanol 90/10). 49 mg of 2(S)-benzyloxy-3-[3′-(3-heptyl-1-methylureido)biphenyl-4-yl]propanoic acid are obtained in the form of an oil. Yield=72%.

후처리

  1. extractionextraction
  2. dry with materialdried over sodium sulfate
  3. customThe solvents are evaporated
  4. customthe residue is chromatographed on silica gel (dichloromethane/methanol 90/10)

출처 및 근거

ORD 기록
ord-db7e3c6458bc44098c77124d166c397a
출처 데이터셋
uspto-grants-2009_12
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07626054B2

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