3-(Boc-amino)piperidine → Hydrochloric Acid

반응식

C(OC([NH:8][CH:9]1[CH2:14][CH2:13][CH2:12][N:11]([S:15]([C:18]2[C:19]3[C:20]([Br:28])=[CH:21][N:22]=[CH:23][C:24]=3[CH:25]=[CH:26][CH:27]=2)(=[O:17])=[O:16])[CH2:10]1)=O)(C)(C)C.BrC1C2C(S([Cl:43])(=O)=O)=CC=CC=2C=NC=1.C(OC(NC1CCCNC1)=O)(C)(C)C>>[NH2:8][CH:9]1[CH2:14][CH2:13][CH2:12][N:11]([S:15]([C:18]2[C:19]3[C:20]([Br:28])=[CH:21][N:22]=[CH:23][C:24]=3[CH:25]=[CH:26][CH:27]=2)(=[O:17])=[O:16])[CH2:10]1.[ClH:43]

참가 물질

반응물 3

HCID 42330413-(Boc-amino)piperidine

HCID 145800584-Bromo-5-isoquinolinesulfonyl chloride

HCID 67242812(r/s)-3-(Tert-butoxycarbonylamino)-1-(4-bromo-5-isoquinolinesulfonyl)piperidine2회

생성물 2

HCID 313Hydrochloric Acid

HCID 67242500(r/s)-3-Amino-1-(4-bromo-5-isoquinolinesulfonyl)piperidine

실험 절차

(R/S)-3-(tert-Butoxycarbonylamino)-1-(4-bromo-5-isoquinolinesulfonyl)-piperidine (Intermediate 2) can be prepared from 4-bromo-5-isoquinolinesulfonyl chloride and 3-(tert-butoxycarbonylamino)piperidine (AstaTech) according to the method described in Example 1-1, Step A, and then used in the method of Example 1-1, Step B in a similar manner to obtain the title compound as hydrochloride.