Sodium Hydroxide → 4-(Benzyloxy)-3-methoxybenzoic acid
반응식
[OH-].[Na+].C[O:4][C:5](=[O:22])[C:6]1[CH:11]=[CH:10][C:9]([O:12][CH2:13][C:14]2[CH:19]=[CH:18][CH:17]=[CH:16][CH:15]=2)=[C:8]([O:20][CH3:21])[CH:7]=1>CO>[CH2:13]([O:12][C:9]1[CH:10]=[CH:11][C:6]([C:5]([OH:22])=[O:4])=[CH:7][C:8]=1[O:20][CH3:21])[C:14]1[CH:15]=[CH:16][CH:17]=[CH:18][CH:19]=1참가 물질
4
실험 절차
A solution of sodium hydroxide (2.0 g) in methanol (50 ml) was added to a solution of 4-benzyloxy-3-methoxy benzoic acid methyl ester (4.64 g) in methanol (50 ml) and refluxed for 4 hrs. After removal of methanol under reduced pressure the residue was dissolved in water (150 ml) and washed with ethyl acetate (2×50 ml). The aqueous layer was acidified with 2N hydrochloric acid to pH 2. The precipitated product was collected by filtration which on drying under vacuum provided 4.17 g of 4-benzyloxy-3-methoxy benzoic acid. (Yield=74%)