Hydrochloric Acid → HCID 67026905, 화합물

HRID 2040782노트

반응식

HRID 2040782 반응식
C([O:4][C:5](=[O:18])[C:6]1[CH:11]=[C:10]([CH3:12])[N:9]=[C:8]([CH:13]([CH2:16][CH3:17])[CH2:14][CH3:15])[CH:7]=1)(C)C.[ClH:19]>>[ClH:19].[CH2:14]([CH:13]([C:8]1[CH:7]=[C:6]([CH:11]=[C:10]([CH3:12])[N:9]=1)[C:5]([OH:18])=[O:4])[CH2:16][CH3:17])[CH3:15]

참가 물질

3

반응물 2

HCID 313Hydrochloric AcidHCID 670271922-(1-Ethylpropyl)-6-methylisonicotinic acid isopropyl ester

생성물 1

HCID 67026905HCID 67026905, 화합물

실험 절차

A solution of 2-(1-ethyl-propyl)-6-methyl-isonicotinic acid isopropyl ester (1.54 g, 6.18 mmol) in 25% aq. HCl (60 mL) is stirred at 65° C. for 16 h. The solvent is removed in vacuo and the residue is dissolved in dioxane and concentrated again to give 2-(1-ethyl-propyl)-6-methyl-isonicotinic acid hydrochloride (1.70 g) as a brownish solid; LC-MS: tR=0.62 min, [M+1]+=208.52.

후처리

  1. customThe solvent is removed in vacuo
  2. dissolutionthe residue is dissolved in dioxane
  3. concentrationconcentrated again

출처 및 근거

ORD 기록
ord-a0949b5dd56b40cabc6f3b740feed326
출처 데이터셋
uspto-grants-2013_11
특허 번호
US08580824B2

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