Hydrogen Bromide → 3-(4-Bromo-phenylsulfanylmethyl)-pyridine
반응식
[Br:1][C:2]1[CH:7]=[CH:6][C:5]([SH:8])=[CH:4][CH:3]=1.Br.Br[CH2:11][C:12]1[CH:13]=[N:14][CH:15]=[CH:16][CH:17]=1.C(=O)([O-])[O-].[K+].[K+]>CC(C)=O>[Br:1][C:2]1[CH:7]=[CH:6][C:5]([S:8][CH2:11][C:12]2[CH:13]=[N:14][CH:15]=[CH:16][CH:17]=2)=[CH:4][CH:3]=1참가 물질
6
실험 절차
Following method of example 9a, reaction of 4-bromo-benzenethiol (4.8 g, 24.1 mmol) with hydrobromic acid salt of 3-bromomethyl-pyridine (6.9 g, 26.5 mmol) and potassium carbonate (7.3 g, 53 mmol) in 91 ml acetone gives the title compound as a yellow solid (5.8 g). MS (m/e): 281 (M+H).
출처 및 근거
- ORD 기록
- ord-70303cb3f2fd4795b0afacdd68d096d4
- 출처 데이터셋
- uspto-grants-2009_08
- 특허 번호
- US07576108B2
반응 노트
불러오는 중…