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Sodium Hydroxide → {o-{5-[(2-Chloro-alpha,alpha,alpha,6-tetrafluoro-p-tolyl)oxy]-2-nitrophenoxy}phenoxy}acetic acid

HRID 21522
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HRID 21522 반응식
[OH-].[Na+].[Cl:3][C:4]1[CH:9]=[C:8]([O:10][C:11]2[CH:12]=[CH:13][C:14]([N+:30]([O-:32])=[O:31])=[C:15]([CH:29]=2)[O:16][C:17]2[CH:28]=[CH:27][CH:26]=[CH:25][C:18]=2[O:19][CH2:20][C:21]([O:23]C)=[O:22])[CH:7]=[C:6]([F:33])[C:5]=1[C:34]([F:37])([F:36])[F:35]>CO>[Cl:3][C:4]1[CH:9]=[C:8]([O:10][C:11]2[CH:12]=[CH:13][C:14]([N+:30]([O-:32])=[O:31])=[C:15]([CH:29]=2)[O:16][C:17]2[CH:28]=[CH:27][CH:26]=[CH:25][C:18]=2[O:19][CH2:20][C:21]([OH:23])=[O:22])[CH:7]=[C:6]([F:33])[C:5]=1[C:34]([F:37])([F:35])[F:36]
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4

반응물 2

HCID 14798Sodium HydroxideHCID 86748719Methyl {o-{5-[(2-chloro-alpha,alpha,alpha,6-tetrafluoro-p-tolyl)oxy]-2-nitrophenoxy}phenoxy}acetate

생성물 1

HCID 86748718{o-{5-[(2-Chloro-alpha,alpha,alpha,6-tetrafluoro-p-tolyl)oxy]-2-nitrophenoxy}phenoxy}acetic acid수율 39.9%

시약·촉매·용매 1

HCID 887Methanol용매

실험 절차

Sodium hydroxide solution (10 mL of a one normal solution, 0.01 mol) is added to a solution of methyl {o-{5-[(2-chloro-α,α,α,6-tetrafluoro-p-tolyl)oxy]-2-nitrophenoxy}phenoxy}acetate (5.25 g, 0.01 mol) in methanol. The reaction mixture is stirred for three hours, concentrated in vacuo and dissolved in water. The aqueous solution is adjusted to pH 3 with 2.5N hydrochloric acid and extracted with methylene chloride. The organic extract is washed with water, dried over anhydrous sodium sulfate and concentrated in vacuo to obtain the title product as a white solid (2 g) which is identified by 1HNMR and 13CNMR spectral analyses.

후처리

  1. concentrationconcentrated in vacuo
  2. dissolutiondissolved in water
  3. extractionextracted with methylene chloride
  4. extractionThe organic extract
  5. washis washed with water
  6. dry with materialdried over anhydrous sodium sulfate
  7. concentrationconcentrated in vacuo

출처 및 근거

ORD 기록
ord-687da6d273c64f0b9c1b8cba3b5ec032
출처 데이터셋
uspto-grants-1995_06
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US05424280

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