Stannous Chloride → Methyl 3-amino-5-(5-methylpyridin-2-yl)benzoate
반응식
[CH3:1][O:2][C:3](=[O:20])[C:4]1[CH:9]=[C:8]([N+:10]([O-])=O)[CH:7]=[C:6]([C:13]2[CH:18]=[CH:17][C:16]([CH3:19])=[CH:15][N:14]=2)[CH:5]=1.Cl[Sn]Cl>CO>[CH3:1][O:2][C:3](=[O:20])[C:4]1[CH:5]=[C:6]([C:13]2[CH:18]=[CH:17][C:16]([CH3:19])=[CH:15][N:14]=2)[CH:7]=[C:8]([NH2:10])[CH:9]=1참가 물질
4
실험 절차
To a solution of 3-(5-Methyl-pyridin-2-yl)-5-nitro-benzoic acid methyl ester (410 mg, 36.9 mmol) in methanol was added SnCl2 (1.36 g, 6.03 mmol) at room temperature. The reaction mixture was refluxed for 3 hours and then cooled. Solvent was removed in vacuo and the residue was dissolved in H2O and basified by Na2CO3 to pH=9. The mixture was extracted with CH2Cl2, and the organic phase was washed with water, brine, and dried over Na2SO4. The solvent was removed under vacuum to give 3-amino-5-(5-methyl-pyridin-2-yl)-benzoic acid methyl ester (362 m g, 100%) as yellow oil. MS (M+H)=244.