Trifluoroacetic acid → 5,6-Dihydrophenanthridine

HRID 2181848노트

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HRID 2181848 반응식
[CH2:1]([C:3]1[N:4]=[C:5]2[C:10](=[C:11]3[C:16]=1[CH:15]=[C:14]([F:17])[CH:13]=[CH:12]3)[CH:9]=[CH:8][CH:7]=[CH:6]2)[CH3:2].[BH4-].[Na+].FC(F)(F)C(O)=O.C1C=CC2C3C=CC=CC=3NCC=2C=1.C(N(CC)CC)C.[Cl:48][C:49]1[CH:50]=[C:51]([S:57](Cl)(=[O:59])=[O:58])[CH:52]=[CH:53][C:54]=1[O:55][CH3:56]>O1CCCC1.ClCCl>[CH:14]1[CH:13]=[CH:12][C:11]2[C:10]3[CH:9]=[CH:8][CH:7]=[CH:6][C:5]=3[NH:4][CH2:3][C:16]=2[CH:15]=1.[CH2:1]([CH:3]1[C:16]2[C:11](=[CH:12][CH:13]=[C:14]([F:17])[CH:15]=2)[C:10]2[CH:9]=[CH:8][CH:7]=[CH:6][C:5]=2[N:4]1[S:57]([C:51]1[CH:52]=[CH:53][C:54]([O:55][CH3:56])=[C:49]([Cl:48])[CH:50]=1)(=[O:58])=[O:59])[CH3:2]

참가 물질

10

실험 절차

The intermediate dihydrophenanthridine was prepared from 6-ethyl-8-fluorophenanthridine, (Example 40, Step b, 0.40 g, 1.8 mmol), by treatment with sodium borohydride (0.40 g, 10.6 mmol) and trifluoroacetic acid (0.55 mL, 7.1 mmol) in tetrahydrofuran (7 mL). In a separate, second step, the dihydrophenanthridine was treated with triethylamine (0.9 mL, 6.4 mmol) and 3-chloro-4-methoxybenzenesulfonyl chloride (0.51 g, 2.1 mmol, 2.1 equivalents) in dichloromethane (5 mL), according to the procedure and in the same manner as described in Example 32, Method A, Step d, to afford 6-ethyl-8-fluoro-5-[(3-chloro-4-methoxyphenyl)sulfonyl]-5,6-dihydrophenanthridine as a crude product, which was utilized without further purification.

출처 및 근거

ORD 기록
ord-1afc60d4b4184dada63199b24b44fd26
출처 데이터셋
uspto-grants-2005_05
특허 번호
US06894061B2

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