Hydrochloric Acid → 2-(3-Methoxyquinolin-6-yl)propanoic acid hydrochloride
반응식
[CH3:1][O:2][C:3]1[CH:4]=[N:5][C:6]2[C:11]([CH:12]=1)=[CH:10][C:9]([CH:13]([CH3:21])[C:14]([O:16]C(C)(C)C)=[O:15])=[CH:8][CH:7]=2.[ClH:22]>CCOC(C)=O>[ClH:22].[CH3:1][O:2][C:3]1[CH:4]=[N:5][C:6]2[C:11]([CH:12]=1)=[CH:10][C:9]([CH:13]([CH3:21])[C:14]([OH:16])=[O:15])=[CH:8][CH:7]=2참가 물질
4
실험 절차
Tert-butyl 2-(3-methoxyquinolin-6-yl)propanoate (0.865 g, 3.01 mmol) was dissolved in EtOAc (0.2M, 15 mL), and HCl (g) (0.0915 ml, 3.01 mmol) was bubbled through the solution for approximately 5 minutes. The reaction vessel was sealed and the reaction was stirred at room temperature for 1.5 h until completion. The reaction mixture was concentrated in vacuo to yield 2-(3-methoxyquinolin-6-yl)propanoic acid hydrochloride (0.805 g, 99.9% yield) as an orange solid.