Sodium Hydroxide → 2-(4-Fluorophenyl)-4-methylpyrimidine-5-carboxylic acid
반응식
C([O:3][C:4]([C:6]1[C:7]([CH3:19])=[N:8][C:9]([C:12]2[CH:17]=[CH:16][C:15]([F:18])=[CH:14][CH:13]=2)=[N:10][CH:11]=1)=[O:5])C.[OH-].[Na+]>CO>[F:18][C:15]1[CH:14]=[CH:13][C:12]([C:9]2[N:8]=[C:7]([CH3:19])[C:6]([C:4]([OH:5])=[O:3])=[CH:11][N:10]=2)=[CH:17][CH:16]=1참가 물질
4
실험 절차
A solution of ethyl-2-(4-fluorophenyl)-4-methylpyrimidine-5-carboxylate (1.65 g, 6.35 mmol) in MeOH (75 mL) is treated with 2 N aqueous sodium hydroxide (10 mL) and heated to reflux for 30 min. MeOH is removed in vacuo and the residue is diluted with water (50 mL). The solution is adjusted to pH ˜2 with 2 M hydrochloric acid. The precipitated is collected by filtration, washed with water and vacuum dried to afford 2-(4-fluorophenyl)-4-methylpyrimidine-5-carboxylic acid (1.3 g, 88%) as a solid. MS: 233 (M+H).