Hydrochloric Acid → 3-[1-(3-methoxyphenyl)-2,2-dioxido-1,4-dihydro-3H-2,1,3-benzothiadiazin-3-yl]-N-methylpropan-1-amine hydrochloride
반응식
[Cl:1][CH2:2][CH2:3][CH2:4][N:5]1[CH2:10][C:9]2[CH:11]=[CH:12][CH:13]=[CH:14][C:8]=2[N:7]([C:15]2[CH:20]=[CH:19][CH:18]=[C:17]([O:21][CH3:22])[CH:16]=2)[S:6]1(=[O:24])=[O:23].[CH3:25][NH2:26].Cl>>[ClH:1].[CH3:22][O:21][C:17]1[CH:16]=[C:15]([N:7]2[C:8]3[CH:14]=[CH:13][CH:12]=[CH:11][C:9]=3[CH2:10][N:5]([CH2:4][CH2:3][CH2:2][NH:26][CH3:25])[S:6]2(=[O:24])=[O:23])[CH:20]=[CH:19][CH:18]=1참가 물질
4
실험 절차
In an analogous manner to Example 1, step 8, 3-(3-chloropropyl)-1-(3-methoxyphenyl)-3,4-dihydro-1H-2,1,3-benzothiadiazine 2,2-dioxide (33 mg) was reacted with methylamine and then treated with HCl to provide 3-[1-(3-methoxyphenyl)-2,2-dioxido-1,4-dihydro-3H-2,1,3-benzothiadiazin-3-yl]-N-methylpropan-1-amine hydrochloride (21 mg):