[CH3:1][C@@H:2]1[C@@H:7]([O:8][C:9](=[O:14])[C:10]([CH3:13])([CH3:12])[CH3:11])[CH2:6][CH2:5][NH:4][CH2:3]1.[OH-].[Na+]>>[CH3:1][C@H:2]1[C@H:7]([O:8][C:9](=[O:14])[C:10]([CH3:13])([CH3:12])[CH3:11])[CH2:6][CH2:5][NH:4][CH2:3]1The mother liquor of 17 from above is treated with 1N—NaOH to obtain the free base which is then crystallized with D-(+)-O,O′-Dibenzoyl tartaric acid as described above to give the antipode 20.
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