Sodium Hydroxide → N2,N4-bis(4-carboxy-3-methoxyphenyl)-5-fluoro-2,4-pyrimidinediamine

HRID 226809

반응식

HRID 226809 반응식
C(C1C=C(NC2N=C(NC3C=CC=C(C(O)=O)C=3)C(F)=CN=2)C=CC=1)(O)=O.[CH3:28][O:29][C:30]1[CH:31]=[C:32]([NH:40][C:41]2[N:46]=[C:45]([NH:47][C:48]3[CH:53]=[CH:52][C:51]([C:54]([O:56]C)=[O:55])=[C:50]([O:58][CH3:59])[CH:49]=3)[C:44]([F:60])=[CH:43][N:42]=2)[CH:33]=[CH:34][C:35]=1[C:36]([O:38]C)=[O:37].[OH-].[Na+]>>[C:36]([C:35]1[CH:34]=[CH:33][C:32]([NH:40][C:41]2[N:46]=[C:45]([NH:47][C:48]3[CH:53]=[CH:52][C:51]([C:54]([OH:56])=[O:55])=[C:50]([O:58][CH3:59])[CH:49]=3)[C:44]([F:60])=[CH:43][N:42]=2)=[CH:31][C:30]=1[O:29][CH3:28])([OH:38])=[O:37]

참가 물질

4

반응물 3

HCID 14798Sodium HydroxideHCID 10126258N2,N4-bis(3-carboxyphenyl)-5-fluoro-2,4-pyrimidinediamineHCID 22060643N2,N4-bis(3-methoxy-4-methoxycarbonylphenyl)-5-fluoro-2,4-pyrimidinediamine

생성물 1

HCID 22060868N2,N4-bis(4-carboxy-3-methoxyphenyl)-5-fluoro-2,4-pyrimidinediamine수율 70%

실험 절차

In a manner analogous to the preparation of N2,N4-bis(3-carboxyphenyl)-5-fluoro-2,4-pyrimidinediamine, N2,N4-bis(3-methoxy-4-methoxycarbonylphenyl)-5-fluoro-2,4-pyrimidinediamine (30 mg, 0.06 mmol) and NaOH (200 mg, 5 mmol) gave N2,N4-bis(4-carboxy-3-methoxyphenyl)-5-fluoro-2,4-pyrimidinediamine (18 mg, 64%) as a white solid.

출처 및 근거

ORD 기록
ord-cae13727090044dbb85ddecc96e76f89
출처 데이터셋
uspto-grants-2009_07
특허 번호
US07557210B2

연결된 노트

불러오는 중…