Hydrochloric Acid → 4-(2-Fluoro-4-nitrophenoxy)quinolin-7-ol
반응식
C([O:8][C:9]1[CH:18]=[C:17]2[C:12]([C:13]([O:19][C:20]3[CH:25]=[CH:24][C:23]([N+:26]([O-:28])=[O:27])=[CH:22][C:21]=3[F:29])=[CH:14][CH:15]=[N:16]2)=[CH:11][CH:10]=1)C1C=CC=CC=1.Cl>O1CCOCC1>[F:29][C:21]1[CH:22]=[C:23]([N+:26]([O-:28])=[O:27])[CH:24]=[CH:25][C:20]=1[O:19][C:13]1[C:12]2[C:17](=[CH:18][C:9]([OH:8])=[CH:10][CH:11]=2)[N:16]=[CH:15][CH:14]=1참가 물질
4
반응 조건
- 온도
- 100 °C
실험 절차
A suspension of 7-(benzyloxy)-4-(2-fluoro-4-nitrophenoxy)quinoline (100 g, 256.4 mmol) in dioxane (425 mL) and conc. HCl (425 mL, 5.1 mol) was stirred at 100° C. for 24 hours. The reaction mixture was then cooled to room temperature and solid was collected through filtration. The solid was then suspended in anhydrous EtOH (100 mL) and stirred for 2 hours. The solid was collected and dried in vacuo at 60° C. for 12 hours to give the title compound as a pale solid (73.3 g, 85%).