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Hexachloroethane → HCID 86686971, 화합물

HRID 2284942
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HRID 2284942 반응식
[F:1][C:2]1[CH:3]=[CH:4][C:5]([NH:8][NH:9][C:10](=O)[CH2:11][N:12]2[CH2:17][CH2:16][N:15]([CH3:18])[CH2:14][CH2:13]2)=[N:6][CH:7]=1.C1(P(C2C=CC=CC=2)C2C=CC=CC=2)C=CC=CC=1.C(N(CC)CC)C.ClC(Cl)(Cl)C(Cl)(Cl)Cl>C1COCC1>[F:1][C:2]1[CH:3]=[CH:4][C:5]2[N:6]([C:10]([CH2:11][N:12]3[CH2:17][CH2:16][N:15]([CH3:18])[CH2:14][CH2:13]3)=[N:9][N:8]=2)[CH:7]=1
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

6

반응물 4

HCID 6214HexachloroethaneHCID 8471TriethylamineHCID 11776TriphenylphosphineHCID 86686972HCID 86686972, 화합물

생성물 1

HCID 86686971HCID 86686971, 화합물수율 89%

시약·촉매·용매 1

HCID 8028Tetrahydrofuran용매

실험 절차

Intermediate 14a (570 mg, 2.13 mmol) was dissolved in THF (20.0 mL) and cooled in an ice/water bath. Triphenylphosphine (1.12 g, 4.27 mmol) was added followed by triethylamine (1.19 mL, 8.54 mmol) and hexachloroethane (1.01 g, 4.27 mmol). The reaction was stirred for 18 h. The mixture was loaded onto an SCX-2 cartridge, washing with MeOH and eluting with 2M NH3 in MeOH. The residue was purified by FCC, using 0-10% [2M NH3 in MeOH] in DCM, to give the title compound (470 mg, 1.89 mmol, 89%). LCMS (Method 1): Rt 0.36 min, m/z 250 [MH+].

후처리

  1. temperaturecooled in an ice/water bath
  2. washwashing with MeOH
  3. washeluting with 2M NH3 in MeOH
  4. customThe residue was purified by FCC

출처 및 근거

ORD 기록
ord-655b05d2670541f98c5c770a436dd818
출처 데이터셋
uspto-grants-2015_09
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US09145413B2

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