[CH3:1][C:2]1[O:3][C:4]([CH3:18])=[CH:5][C:6]=1[S:7][C:8]1[CH:13]=[CH:12][C:11]([CH3:14])=[CH:10][C:9]=1[N+:15]([O-])=O.Cl[Sn]Cl>>[CH3:1][C:2]1[O:3][C:4]([CH3:18])=[CH:5][C:6]=1[S:7][C:8]1[CH:13]=[CH:12][C:11]([CH3:14])=[CH:10][C:9]=1[NH2:15]The product from Example 91a was reduced with SnCl2 following the procedure from Example 1f to give the title compound.
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