Sodium Hydroxide → 2-(3-Isopropyl-ureido)-isonicotinic acid
반응식
C([O:3][C:4](=[O:18])[C:5]1[CH:10]=[CH:9][N:8]=[C:7]([NH:11][C:12]([NH:14][CH:15]([CH3:17])[CH3:16])=[O:13])[CH:6]=1)C.[OH-].[Na+]>CO>[CH:15]([NH:14][C:12](=[O:13])[NH:11][C:7]1[CH:6]=[C:5]([CH:10]=[CH:9][N:8]=1)[C:4]([OH:18])=[O:3])([CH3:17])[CH3:16]참가 물질
4
실험 절차
To a solution of 2-(3-Isopropyl-ureido)-isonicotinic acid ethyl ester (130 mg, 0.52 mmol) in MeOH (5 ml) is added 2 M NaOH (2.5 ml) and the resulting solution is stirred for 1.5 hours at room temperature. The solvent is removed in vacuo and sat. aq. NH4Cl solution is added. The pH of the aqueous phase is adjusted to 1 using 1 M HCl and the product extracted into EtOAc, dried (MgSO4) the solvent removed in vacuo to afford 2-(3-Isopropyl-ureido)-isonicotinic acid as a white solid; [M+H]+ 224
후처리
- customThe solvent is removed in vacuo and sat. aq. NH4Cl solution
- additionis added
- extractionthe product extracted into EtOAc
- dry with materialdried (MgSO4) the solvent
- customremoved in vacuo
출처 및 근거
- ORD 기록
- ord-e870214c5d864af98bea87b6e32c147f
- 출처 데이터셋
- uspto-grants-2014_04
- 특허 번호
- US08697687B2
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