Sodium Hydroxide → HCID 135984744, 화합물

반응식

N1C2C(=O)OC(=O)C=2C=CN=1.C[O:13][C:14]([C:16]1[N:25]=[CH:24][C:23]2[CH:22]=[CH:21][N:20]=[N:19][C:18]=2[C:17]=1[OH:26])=[O:15].[OH-].[Na+]>>[OH:26][C:17]1[C:18]2[N:19]=[N:20][CH:21]=[CH:22][C:23]=2[CH:24]=[N:25][C:16]=1[C:14]([OH:15])=[O:13]

참가 물질

반응물 3

HCID 14798Sodium Hydroxide

HCID 45082029Furo[3,4-c]pyridazine-5,7-dione

HCID 135984737HCID 135984737, 화합물

생성물 1

HCID 135984744HCID 135984744, 화합물

실험 절차

As shown in Example 1, furo[3,4-c]pyridazine-5,7-dione 1.4 (WO 994492) is converted, as described above, into 8-hydroxy-pyrido[4,3-c]pyridazine-7-carboxylic acid methyl ester 1.5, and the ester is hydrolyzed with sodium hydroxide to give 8-hydroxy-pyrido[4,3-c]pyridazine-7-carboxylic acid 1.6.

출처 및 근거

ORD 기록: ord-57250bf7061b4f0b96036dc0c9a495b2
출처 데이터셋: uspto-grants-2008_12
DOI: 10.6084/m9.figshare.5104873.v1
특허 번호: US07462721B2

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