Hydrochloric Acid → 2-Amino-5-chloro-4-(4-pyridylthiomethyl)thiazole

반응식

[Cl:1][C:2]1[S:6][C:5]([NH:7]C=O)=[N:4][C:3]=1[CH2:10][S:11][C:12]1[CH:17]=[CH:16][N:15]=[CH:14][CH:13]=1.O1CCCC1.Cl>C(O)C>[NH2:7][C:5]1[S:6][C:2]([Cl:1])=[C:3]([CH2:10][S:11][C:12]2[CH:17]=[CH:16][N:15]=[CH:14][CH:13]=2)[N:4]=1

참가 물질

실험 절차

A solution of 5-chloro-2-formylamino-4-(4-pyridylthiomethyl)thiazole (4.9 g) in a mixture of ethanol (25 ml), tetrahydrofuran (20 ml) and concentrated hydrochloric acid (7 ml) was stirred at room temperature for 4 hours. The reaction mixture was concentrated under reduced pressure and the residue was dissolved in water. The solution was adjusted to pH 8 using aqueous sodium bicarbonate under ice-cooling. The precipitates were collected by filtration, washed with water and dried in vacuo to give 2-amino-5-chloro-4-(4-pyridylthiomethyl)thiazole (0.26 g, yield: 56.6%).