Lithium Hydroxide → 2-(3-Fluorophenyl)pyrimidine-5-carboxylic acid
반응식
C[O:2][C:3]([C:5]1[CH:6]=[N:7][C:8]([C:11]2[CH:16]=[CH:15][CH:14]=[C:13]([F:17])[CH:12]=2)=[N:9][CH:10]=1)=[O:4].[Li+].[OH-]>CO>[F:17][C:13]1[CH:12]=[C:11]([C:8]2[N:7]=[CH:6][C:5]([C:3]([OH:4])=[O:2])=[CH:10][N:9]=2)[CH:16]=[CH:15][CH:14]=1참가 물질
4
실험 절차
To a solution of 2-(3-fluoro-phenyl)-pyrimidine-5-carboxylic acid methyl ester (1.76 g, 7.58 mmol) in anhydrous MeOH (35 mL) is added LiOH (0.38 g, 15.9 mmol) and the reaction mixture is stirred at rt overnight. The mixture is concentrated in vacuo and the residue is partitioned between EtOAc and 3 N aqueous HCl (7.6 mL). The mixture is extracted with EtOAc and the organic layer is washed with brine, dried (MgSO4), filtered and concentrated in vacuo to afford 2-(3-fluoro-phenyl)-pyrimidine-5-carboxylic acid (1.62 g, 98%) as a solid. MS: 219 (M+H).