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3-(Boc-amino)piperidine → Hydrochloric Acid

HRID 2425390
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HRID 2425390 반응식
[F:1][C:2]1[C:11]2[C:10]([S:12]([Cl:15])(=[O:14])=[O:13])=[CH:9][CH:8]=[CH:7][C:6]=2[CH:5]=[N:4][CH:3]=1.[C:16]([O:20][C:21]([NH:23][CH:24]1[CH2:29][CH2:28][CH2:27][NH:26][CH2:25]1)=[O:22])([CH3:19])([CH3:18])[CH3:17]>>[C:16]([O:20][C:21]([NH:23][C@H:24]1[CH2:29][CH2:28][CH2:27][N:26]([S:12]([C:10]2[C:11]3[C:2]([F:1])=[CH:3][N:4]=[CH:5][C:6]=3[CH:7]=[CH:8][CH:9]=2)(=[O:14])=[O:13])[CH2:25]1)=[O:22])([CH3:19])([CH3:17])[CH3:18].[NH2:23][C@H:24]1[CH2:29][CH2:28][CH2:27][N:26]([S:12]([C:10]2[C:11]3[C:2]([F:1])=[CH:3][N:4]=[CH:5][C:6]=3[CH:7]=[CH:8][CH:9]=2)(=[O:14])=[O:13])[CH2:25]1.[ClH:15]
참가 물질실험 절차출처 및 근거반응 노트

참가 물질

5

반응물 2

HCID 42330413-(Boc-amino)piperidineHCID 118565474-Fluoroisoquinoline-5-sulfonylchloride

생성물 3

HCID 313Hydrochloric Acid수율 1,222.2%HCID 67242640(S)-3-(tert-Butoxycarbonylamino)-1-(4-fluoro-5-isoquinolinesulfonyl)piperidineHCID 67244923(S)-3-Amino-1-(4-fluoro-5-isoquinolinesulfonyl)piperidine

실험 절차

(S)-3-(tert-Butoxycarbonylamino)-1-(4-fluoro-5-isoquinolinesulfonyl)piperidine (Intermediate 17a) was prepared from 4-fluoro-5-isoquinolinesulfonyl chloride (172 mg) and 3-(tert-butoxycarbonylamino)piperidine (168 mg) according to the method of Example 1-1, Step A, and then used in the method of Example 1-1, Step B in a similar manner to obtain the title compound as hydrochloride (156 mg).

출처 및 근거

ORD 기록
ord-64025c1876444740a21ea476c04a2bd9
출처 데이터셋
uspto-grants-2011_06
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07964613B2

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