홈MCP워크벤치Skills
홈워크벤치알림마이페이지
llms.txt · MCP 가이드개인정보처리방침 · 이용약관 · 지원v1.8.0
  1. 홈
  2. /반응

Sodium Hydroxide → HCID 11670857, 화합물

HRID 250905
노트
인쇄 미리보기

반응식

HRID 250905 반응식
[OH-].[Na+].[F:3][C:4]1[CH:41]=[CH:40][C:7]([CH2:8][O:9][C:10]2[CH:15]=[C:14]([CH2:16][CH2:17][C:18]([O:20]C)=[O:19])[CH:13]=[CH:12][C:11]=2[C:22]2[CH:27]=[CH:26][CH:25]=[C:24]([N:28]([CH3:39])[C:29]([NH:31][CH2:32][CH2:33][CH2:34][CH2:35][CH2:36][CH2:37][CH3:38])=[O:30])[CH:23]=2)=[CH:6][CH:5]=1>O1CCCC1.CO>[F:3][C:4]1[CH:5]=[CH:6][C:7]([CH2:8][O:9][C:10]2[CH:15]=[C:14]([CH2:16][CH2:17][C:18]([OH:20])=[O:19])[CH:13]=[CH:12][C:11]=2[C:22]2[CH:27]=[CH:26][CH:25]=[C:24]([N:28]([CH3:39])[C:29]([NH:31][CH2:32][CH2:33][CH2:34][CH2:35][CH2:36][CH2:37][CH3:38])=[O:30])[CH:23]=2)=[CH:40][CH:41]=1
참가 물질실험 절차후처리출처 및 근거반응 노트

참가 물질

4

반응물 2

HCID 14798Sodium HydroxideHCID 67271470HCID 67271470, 화합물

생성물 1

HCID 11670857HCID 11670857, 화합물수율 64%

시약·촉매·용매 1

HCID 21899815MeOH tetrahydrofuran용매

실험 절차

In a manner similar to that of Example (19g), by reaction of 400 mg (10 mmol, 10 eq) of sodium hydroxide and methyl 3-[2-(4-fluorobenzyloxy)-3′-(3-heptyl-1-methylureido)biphenyl-4-yl]propanoate, obtained in the preceding step, in 10 ml of a tetrahydrofuran/methanol mixture (8/2), and after crystallization from pentane, 310 mg of 3-[2-(4-fluorobenzyloxy)-3′-(3-heptyl-1-methylureido)biphenyl-4-yl]propanoic acid are obtained in the form of a white powder (m.p.=79° C.). Yield=64% over the two steps.

후처리

  1. customafter crystallization from pentane, 310 mg of 3-[2-(4-fluorobenzyloxy)-3′-(3-heptyl-1-methylureido)biphenyl-4-yl]propanoic acid

출처 및 근거

ORD 기록
ord-cab21f5fcfac4af59129c2c7c3deb19d
출처 데이터셋
uspto-grants-2011_01
DOI
10.6084/m9.figshare.5104873.v1
특허 번호
US07863332B2

반응 노트

불러오는 중…

이 페이지에서참가 물질실험 절차후처리출처 및 근거반응 노트