Tetrahydrofuran → HCID 178527461, 화합물

HRID 25358

반응식

HRID 25358 반응식
[NH2:1][C:2]1[CH:3]=[C:4]2[C:8](=[CH:9][CH:10]=1)[NH:7][N:6]=[C:5]2[Cl:11].O1CCCC1.[F:17][C:18]1[CH:19]=[C:20]([S:24](Cl)(=[O:26])=[O:25])[CH:21]=[CH:22][CH:23]=1>C(N(CC)CC)C>[Cl:11][C:5]1[C:4]2[C:8](=[CH:9][CH:10]=[C:2]([NH:1][S:24]([C:20]3[CH:21]=[CH:22][CH:23]=[C:18]([F:17])[CH:19]=3)(=[O:26])=[O:25])[CH:3]=2)[NH:7][N:6]=1

참가 물질

5

반응물 3

HCID 8028TetrahydrofuranHCID 27342583-Fluorobenzenesulfonyl ChlorideHCID 178507360HCID 178507360, 화합물

생성물 1

HCID 178527461HCID 178527461, 화합물수율 37.2%

시약·촉매·용매 1

HCID 8471Triethylamine용매

실험 절차

N-(3-Chloro-1H-indazol-5-yl)-3-fluorobenzenesulfonamide can be obtained as described in Example 1 from 0.18 g of 5-amino-3-chloro-1H-indazole, 20 ml of tetrahydrofuran, 0.25 ml of triethylamine and 0.23 g of 3-fluorobenzenesulfonyl chloride. 0.13 g of N-(3-chloro-1H-indazol-5-yl)-3-fluorobenzenesulfonamide is thus obtained in the form of a yellow foam which decomposes at approximately 80° C. (analysis C13H9ClFN3O2S % calculated: 47.93; H, 2.78; Cl, 10.88; F, 5.83; N, 12.90; O, 9.82; S, 9.84. % found C, 48.11; H, 2.64; F, 5.14; N, 13.14; S, 8.22).

출처 및 근거

ORD 기록
ord-84f1951deb144a93ad4d95396efe02fa
출처 데이터셋
uspto-grants-2005_02
특허 번호
US06858638B2

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