Hydrochloric Acid → 2-Cyclopropyl-4-cyclopropylamino-6-morpholino-1,3,5-triazine

HRID 256710

반응식

HRID 256710 반응식
Cl.C(O)C.C(OCC)C.Cl.[CH:11]1([C:14]2[N:19]=[C:18]([NH:20][CH:21]3[CH2:23][CH2:22]3)[N:17]=[C:16]([N:24]3[CH2:29][CH2:28][O:27][CH2:26][CH2:25]3)[N:15]=2)[CH2:13][CH2:12]1>C(#N)C>[CH:11]1([C:14]2[N:19]=[C:18]([NH:20][CH:21]3[CH2:23][CH2:22]3)[N:17]=[C:16]([N:24]3[CH2:25][CH2:26][O:27][CH2:28][CH2:29]3)[N:15]=2)[CH2:12][CH2:13]1

참가 물질

5

반응물 3

HCID 313Hydrochloric AcidHCID 30733481,3,5-Triazin-2-amine, N,4-dicyclopropyl-6-(4-morpholinyl)-, monohydrochlorideHCID 21585056Diethyl ether ethanol

생성물 1

HCID 30733492-Cyclopropyl-4-cyclopropylamino-6-morpholino-1,3,5-triazine

시약·촉매·용매 1

HCID 6342Acetonitrile용매

실험 절차

2.85 g (0.050 mole) of cyclopropylamine dissolved in 20 ml of dioxane are added to a solution of 5.1 g (0.021 mole) of 2-chloro-4-cyclopropyl-6-morpholino-1,3,5-triazine in 50 ml of dioxane at room temperature. The mixture is heated under reflux for 5 hours. The solvent is then evaporated under reduced pressure and the residue is dissolved in 50 ml of dichloromethane and 50 ml of water. The organic phase is separated off and dried over sodium sulfate and the solvent is evaporated under reduced pressure. The residue crystallizes from cold hexane. 5.22 g of product are obtained. This product forms a hydrochloride in an ethanol-diethyl ether mixture. 5.1 g of 2-cyclopropyl-4-cyclopropylamino-6-morpholino-1,3,5-triazine hydrochloride, which is identical to compound 3 prepared in example 2. B.1., are obtained. Yield: 81.7%. M.P.: 183°-184° C. (acetonitrile).

후처리

  1. custom, are obtained

출처 및 근거

ORD 기록
ord-1d0d5a106dfd4eb3ad90504e0a42a37f
출처 데이터셋
uspto-grants-1993_11
특허 번호
US05258513

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